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Refactored code and added app as a parameter in get_stripe_plan_id

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M.Ravi 2017-08-17 18:21:53 +02:00
parent b0b1b6091a
commit 5fe6007ad2
1 changed files with 5 additions and 3 deletions
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8
utils/stripe_utils.py
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@ -1,7 +1,9 @@
import logging
import stripe
from django.conf import settings
from datacenterlight.models import StripePlan
import logging
stripe.api_key = settings.STRIPE_API_PRIVATE_KEY
logger = logging.getLogger(__name__)
@ -220,7 +222,7 @@ class StripeUtils(object):
return charge
@staticmethod
def get_stripe_plan_id_string(cpu, ram, ssd, version):
def get_stripe_plan_id(cpu, ram, ssd, version, app):
"""
Returns the stripe plan id string of the form `dcl-v1-cpu-2-ram-5gb-ssd-10gb` based on the input parameters
@ -231,5 +233,5 @@ class StripeUtils(object):
:return: A string of the form `dcl-v1-cpu-2-ram-5gb-ssd-10gb`
"""
dcl_plan_string = 'cpu-{cpu}-ram-{ram}gb-ssd-{ssd}gb'.format(cpu=cpu, ram=ram, ssd=ssd)
stripe_plan_id_string = '{app}-v{version}-{plan}'.format(app='dcl', version=version, plan=dcl_plan_string)
stripe_plan_id_string = '{app}-v{version}-{plan}'.format(app=app, version=version, plan=dcl_plan_string)
return stripe_plan_id_string