66 lines
2.2 KiB
Bash
66 lines
2.2 KiB
Bash
#!/bin/sh
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#
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# -------------------------------------------------------------
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# Get the real disk usage for a group of selected files
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#
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# This script counts the size of the files and directories
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# listed, but exclude files that have hard links referenced outside
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# the list.
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#
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# The undelying objective of this script is to report the
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# real amount of disk used for backup solutions that are heavily
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# using hard links to save disk space on identical files (I use
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# ccollect, but this likely works with rsnapshot)
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# -------------------------------------------------------------
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# 20091002 - initial release - pdrolet (rdu@drolet.name)
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# --------------------
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# Parse options
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# --------------------
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# Known problem:
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# - Command line cannot get a directory with a space in it
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#
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kdivider=1
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find_options=""
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while [ "$#" -ge 1 ]; do
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case "$1" in
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-m)
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kdivider=1024
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;;
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-g)
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kdivider=1048576
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;;
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-h|--help)
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echo
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echo $0: \<directories\> \[options below and any \"find\" options\]
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echo \ \ -m: result in mega bytes \(rounded up\)
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echo \ \ -g: result in giga bytes \(rounded up\)
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echo \ \ -h: this help
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echo
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exit 0
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;;
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*)
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find_options="${find_options} $1"
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;;
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esac
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shift
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done
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# ------------------------------------------------------------------------------------------------------
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# Compute the size
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# ------------------------------------------------------------------------------------------------------
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# 1) Find selected files and list link count, inodes, file type and size
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# 2) Sort (sorts on inodes since link count is constant per inode)
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# 3) Merge duplicates using uniq
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# (result is occurence count, link count, inode, file type and size)
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# 4) Use awk to sum up the file size of each inodes when the occurence count
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# and link count are the same. Use %k for size since awk's printf is 32 bits
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# 5) Present the result with additional dividers based on command line parameters
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#
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echo $((( `find ${find_options} -printf '%n %i %y %k \n' \
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| sort -n \
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| uniq -c \
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| awk '{ if (( $1 == $2 ) || ($4 == "d")) { sum += $5; } } END { printf "%u\n",(sum); }'` \
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+ ${kdivider} -1 ) / ${kdivider} ))
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