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Refactor set_subscription_id - use stripe subscription id instead of obj

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This commit is contained in:
M.Ravi 2017-09-29 08:42:17 +02:00
parent caad79304b
commit 313ba9d502
1 changed files with 5 additions and 5 deletions
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10
hosting/models.py
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@ -88,19 +88,19 @@ class HostingOrder(AssignPermissionsMixin, models.Model):
self.cc_brand = stripe_charge.source.brand self.cc_brand = stripe_charge.source.brand
self.save() self.save()
def set_subscription_id(self, subscription_object, cc_details): def set_subscription_id(self, subscription_id, cc_details):
""" """
When creating a Stripe subscription, we have subscription id. When creating a Stripe subscription, we have subscription id.
We store this in the subscription_id field. We store this in the subscription_id field.
This method sets the subscription id from subscription_object This method sets the subscription id
and also the last4 and credit card brands used for this order. and the last4 and credit card brands used for this order.
:param subscription_object: Stripe's subscription object :param subscription_id: Stripe's subscription id
:param cc_details: A dict containing card details :param cc_details: A dict containing card details
{last4, brand} {last4, brand}
:return: :return:
""" """
self.subscription_id = subscription_object.id self.subscription_id = subscription_id
self.last4 = cc_details.get('last4') self.last4 = cc_details.get('last4')
self.cc_brand = cc_details.get('brand') self.cc_brand = cc_details.get('brand')
self.save() self.save()