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Make url URLField

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This commit is contained in:
PCoder 2021-11-26 16:47:09 +05:30
parent 0bbe1fd80d
commit 8b2508fbc5
3 changed files with 21 additions and 1 deletions
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2
app/management/commands/import.py
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@ -411,6 +411,8 @@ class Command(BaseCommand):
def handle_object_dict(object_dict, model_name): def handle_object_dict(object_dict, model_name):
if model_name == 'Resource':
object_dict['url'] = object_dict['url'].strip("#")
if model_name == 'Range': if model_name == 'Range':
# Reinstate range_name key # Reinstate range_name key
object_dict['range_name'] = object_dict['range_name_id'] object_dict['range_name'] = object_dict['range_name_id']

18
app/migrations/0025_alter_resource_url.py Normal file
View file

@ -0,0 +1,18 @@
# Generated by Django 3.2.5 on 2021-11-26 11:16
from django.db import migrations, models
class Migration(migrations.Migration):
dependencies = [
('app', '0024_alter_resource_stars'),
]
operations = [
migrations.AlterField(
model_name='resource',
name='url',
field=models.URLField(blank=True, null=True),
),
]

2
app/models.py
View file

@ -159,7 +159,7 @@ class Resource(models.Model):
id = models.AutoField(primary_key=True) id = models.AutoField(primary_key=True)
source_id = models.IntegerField(blank=True, null=True) source_id = models.IntegerField(blank=True, null=True)
title = models.TextField(blank=True, null=True) title = models.TextField(blank=True, null=True)
url = models.TextField(blank=True, null=True) url = models.URLField(blank=True, null=True)
citation = models.TextField(blank=True, null=True) citation = models.TextField(blank=True, null=True)
abstract = models.TextField(blank=True, null=True) abstract = models.TextField(blank=True, null=True)